Lesson

Lesson Title: Laws of Indices.


Objectives :

At the end of this lesson, you will be able to,

1. Identify the laws of indices - Multiplication, Division, and Product law.

2. Solve problems relating to laws of indices.

3. Understand the concepts behind Zero Indices, Negative Indices, and Fractional Indices.


What you should know :

You should be familiar with BODMAS precedence and other basic arithmetic operations.


Introduction :

The word indices is the plural form of an index. Index a is the number of times a number n must multiply itself to equal a certain number b, that is,

na = b.


Presentation /Steps


1. The Multiplication Law.

=> an * an * an = an+n+n Where the base values a are the same.

=> a3 * a2 = a3+2 = a5

=> 102 * 10 = 102+1 = 103

N.B any value raised to the index of 1 is still that value.

=> 2a2 * 3a4 * 4a2 = (2*3*4)a2+4+2

N.B 2a is the same as 2*a likewise 3*a, and 4*a, since a is the affected value and they are similar, then a2+4+2 ,

Therefore, the final answer will be,

(24)a8 = 24a8 .


2. The Division Law.

=> In this law, the indices are subtracted, unlike multiplication law where the indices are added.

=> an ÷ an = an-n . Where the base values a are the same.

=> C4 ÷ C2 = C4-2 = C2

=> 37 ÷ 32 = 37-2 = 35

=> 24b9 ÷ 4b3 = (24 ÷ 4)b9-3 = 6b6


3. The Product Laws.

=> In this law, the index outside the bracket multiplies the indices inside the bracket.

=> N:B, A value raised to an index 1 is still the same value, so there is no need to write the index '1'.

=> (Xa)b = Xa*b

=> (2xa)b is the same as 2b * Xa*b = 2bxa*b

=> (g-3)2 = g-3*2 = g-6

=> (-4b)2 = (-4)2 * b2 ==> -4 * -4 = 8 * b2 = 8b2

=> (-4b)3 = (-4)3 * b3 ==>

-4 * -4 * -4 = -32 * b3 = -32b3

N:B If a negative number is raised to an odd index, the number remains negative,

but, if a negative number is raised to an even index, the number changes to a positive number.


4. Zero Indices.

A value raised to the index of 0 equals 1.

a0 = 1.

=> a-2 * a2 = a-2 + 2 = a0 = 1.

=> b3 ÷ b3 = b3 - 3 = b0 = 1.


5. Negative Indices.

=> a-x = 1/ax

=> 2a-x = (2)1/ax = 2/ax

=> The negative index is often used when the final result of an expression has a negative index.


6. Fractional Indices.

=> X1/a , Xc/b

=> In this case, the fractional part is used for the calculation, the denominator of the expressions above (a, b) is used as the root of the value x while (1, c) is used as the power index.

=> That is (a√x)1, (b√x)c

=> 4½ = √4 = ± 2.

N:B "2" is not indicated as the root value because √ represents the square root by default, you can only include a root value when the value is above 2.

=> 27⅔ = (3√27)2 = (3)2 = ± 9.


Summary / Conclusion:

In this lesson, we were able to solve problems by applying the laws of indices and other indices sub-laws.

=> Indices help in writing LCMs of a number in a short form: the LCM of 16 = 2 * 2 * 2 * 2 which can be shortened as 24


Exercise :

Express the following 8-⅔ , (a3b)4

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